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How to Create a Symmetric Array in Python

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 Here's a Python program that says to write a Symmetric array transformation. A top interview question. Symmetric Array Transformation Problem: Write a Python function that transforms a given array into a symmetric array by mirroring it around its center. For example: Input: [1, 2, 3] Output: [1, 2, 3, 2, 1] Hints: Use slicing for the reverse part. Concatenate the original array with its mirrored part. Example def symmetric_array(arr):     """     Transforms the input array into a symmetric array by mirroring it around its center.     Parameters:     arr (list): The input array.     Returns:     list: The symmetric array.     """     # Mirror the array by concatenating the original with its reverse (excluding the last element to avoid duplication)     return arr + arr[-2::-1] # Example usage input_array = [1, 2, 3] symmetric_result = symmetric_array(input_array) print("Input Array:", input_arr...

The Quick and Easy Way to Fix Python UnboundLocalError

Here is the easy way to fix the issue of the Python UnboundLocalError, allowing users to resolve any problems quickly.


UnboundLocalError



Python UnboundLocalError

While the variable in the function has already been defined, during execution, the result prints with an error of UnboundLocalError. Below, you will find an example that explains the issue and resolution.

Error: file 'example.txt' not found
Traceback (most recent call last):
File "main.py", line 16, in <module>
open_file("example.txt")
File "main.py", line 11, in open_file
if f:
UnboundLocalError: local variable 'f' referenced before assignment


** Process exited - Return Code: 1 **

Press Enter to exit terminal


Python program using try, except and finally

Below program explains how to use try, except and finally blocks in python. But during the execution, it prints UnboundLocalError.


Program using try, except and finally

# Define a function that may raise an exception
def open_file(filename):
    try:
        f = open(filename, "r")
        contents = f.read()
    except FileNotFoundError:
        print(f"Error: file '{filename}' not found")
    else:
        print(f"Contents of file '{filename}':\n{contents}")
    finally:
        if f:
            f.close()
            print(f"File '{filename}' has been closed.")

# Call the function with a valid filename
open_file("example.txt")

# Call the function with an invalid filename
open_file("invalid.txt")


The output:

Error: file 'example.txt' not found
Traceback (most recent call last):
  File "main.py", line 16, in <module>
    open_file("example.txt")
  File "main.py", line 11, in open_file
    if f:
UnboundLocalError: local variable 'f' referenced before assignment


** Process exited - Return Code: 1 **
Press Enter to exit terminal

Resolution for UnboundLocalError

In the function, before the try block, add f = None. That resolves the issue. Here is the corrected program.

Corrected program

# Define a function that may raise an exception
def open_file(filename):
    try:
        f = None
        f = open(filename, "r")
            contents = f.read()
    except FileNotFoundError:
        print(f"Error: file '{filename}' not found")
    else:
        print(f"Contents of file '{filename}':\n{contents}")
    finally:
        if f:
            f.close()
            print(f"File '{filename}' has been closed.")

# Call the function with a valid filename
open_file("example.txt")

# Call the function with an invalid filename
open_file("invalid.txt")


The output is:

Error: file 'example.txt' not found
Error: file 'invalid.txt' not found


** Process exited - Return Code: 0 **
Press Enter to exit terminal


Summary

  • Return statement not coded in the function. As a result, it gave UnboundLocalError.
  • A function returns the None object by default if the control flow falls off the end of the function body without running into a return statement.

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